Please help:) What does this mean? \(\exists x, y \in Z \ni d=ax+by\)
Well \(\mathbb{Z}\) means integers... that is ... -3, -2, -1, 0, 1, 2, 3, ...
ya actually I want to knw what the symbol \(\ni\) means?
So you're saying there exist the integers x, and y, where if you multiply by a and b, you end up with another integer.
It's just "in this set"
and "in the integer set" basically means "is an integer"
The \( \exists\) symbol means that the number/thingy exists.
and it satisfies whatever equation/properties/etc follow
So that means there exist integers x and y such that ax+by=d is also an integer. Am I right?@wio
I would translate that expression to say: "There exists two integers, \(x\) and \(y\), such that \(ax+by\) is an integer.
@ajprincess Yeah. I think the \(d\) is just there for the sake of saying the result is an integer.
oh k. thanx a lot:)
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