Question

Which of the following is not an equivalent form of the compound inequality

x + 12 > 20 and x + 12 less than or greater to 26

20 < x + 12 less than or greater to 26

A number line with a closed circle on 14, shading to the right, and an open circle on 8, shading to the left.

8 < x and x less than or greater to 14

A number line with a closed circle on 14, an open circle on 8, and shading in between.

Answer 1

1st and 2nd statements are equivalent

Answer 2

A number line with a closed circle on 14, shading to the right, and an open circle on 8, shading to the left.

Answer 3

are u sure its less than or greater to............it should be less than or equal to

Answer 4

3rd anrd 4th staements are not equivalent

Answer 5

3rd and 5th are also not equivalent

Answer 6

20 < x + 12 less than or greater to 26

Answer 7

@nitz

Answer 8

well why dont we solve each of them together ..i think that will help you more !

Answer 9

@nitz please do not provide direct answers ..instead help the asker to get to the solution thank you

Answer 10

sorry @ivandelgado i was busy with another question

Answer 11

should i explain @ivandelgado

Answer 12

yes

Answer 13

@nitz

Answer 14

ok firstly are u sure its less than or greater to

Answer 15

yes

Answer 16

ok

Answer 17

firstly we will see why 1st and 2nd are equivalent

Answer 18

@ivandelgado rearrange the equations in part a so that x is in lhs and all other numbers go to RHS

Answer 19

its the method of solving inequalities

Answer 20

make an effort !

Answer 21

x+12>20 and x+12 less than or greater to 26
and we can write it as 20<x+12 which is less than or greater to 26

Answer 22

like 4>3 or equivalently 3<4 one and the same thing

Answer 23

@ivandelgado please interact !