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how to integrate 12/(2x+1)*2 not by substitution.
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first take the constant out \[\int\limits_{?}^{?}\frac{ 12 }{ (2x+1)^2 }dx=12\int\limits_{?}^{?}\frac{ 1 }{ (2x+1)^2 }dx\]
you there?
yeah thanks..:)
do you know how to continue?
yeah i do. :)
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I got the result already if you want us to compare
it's -6/2x+1?
oh and +7
yep
thanks :)
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-6/2x+1 i dont know about the +7
\[12 \int\limits_{}^{} (2x+1)^-2 dx = \frac{ 1 }{ 2 } \frac{ (2x+1}^-2{ -1 } = \frac{ -6 }{ 2x+1 }+c\]
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