Find the vertex of the parabola:

Question

anonymous · Answer

$$y=3x ^{2}+2x-1$$

anonymous · Answer

dy/dx = 6x + 2

At the vertex, dy/dx = 0
Therefore, 6x+2 = 0
Therefore, x = -1/3 

Find the corresponding value of y by substituting this x in the equation of parabola. 

The point (x,y) would be the required vertex

anonymous · Answer

if this is not a calculus course, (and i suspect that it is not) you can find the vertex of $y=ax^2+bx+c$ by using the following:
the first coordinate of the vertex is $-\frac{b}{2a}$ 
in your case it is $-\frac{2}{2\times 3}=-\frac{1}{3}$

anonymous · Answer

the second coordinate of the vertex is what you get when you replace $x$ by $-\frac{1}{3}$

anonymous · Answer

if you do it carefully you should find that the vertex is 
$$(-\frac{1}{3},-\frac{4}{3})$$

anonymous · Answer

Thanks so much! @satellite73