Question

Suppose
a+4b+9c+16d+25e=-13,
4a+9b+16c +25d +36e =-8,
9a+16b+25c+36d+49e=3,
Find the value of 16a+25b+36c+49d+64e=?

Answer 1

I dont think there is only one answer

Answer 2

how

Answer 3

we 3 equation and 5 variables

Answer 4

have^

Answer 5

so. we have to calculate these three equation in such a way that , we get a value of 16a+25b+36c+49d+64e=?

Answer 6

But there will be many solutions

Answer 7

okay..

Answer 8

I guess we will have to transform the 3 given eqns so that we reach the 4th required eqn.

Answer 9

yup..this is vat i m trying 2 say

Answer 10

got it!
multiply 2nd eqn by -3 and 3rd eqn by +3

and add all the 3 equations together

This should help.

Answer 11

x^2 -3(x+1)^2+3(x+2)^2
x^2-3x^2 -6x-3 +3x^2 + 12x+12
x^2 +6x + 9
(x+3)^2

Answer 12

That works @shubhamsrg

Answer 13

px^2 +q(x+1)^2 + r(x+2)^2
(p+q+r)x^2 + (2q+4r)x + (q+4r)
So,
p+q+r=1 ..i
2q+4r=6 ........ii
q+4r=9.............iii

Answer 14

Solve that three equations and multiply all three equations
a+4b+9c+16d+25e=-13,
4a+9b+16c +25d +36e =-8,
9a+16b+25c+36d+49e=3,
with p,q and respectively and add all of the three equations
u will get the value of 16a+25b+36c+49d+64e

Answer 15

(p,q and r)*

Answer 16

U will get p=1 q=-3 and r=3

Answer 17

thank u so much @shubhamsrg