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Mathematics 22 Online
OpenStudy (anonymous):

what's the rule for graphing absolute values when there is a negative sign in front of the absolute value? \[y=-|x-2|\]

OpenStudy (anonymous):

@satellite73 @BluFoot

OpenStudy (anonymous):

here is \(y=|x-2|\) free hand |dw:1358093601371:dw|

OpenStudy (anonymous):

if you want \(y=-|x-2|\) flip it over the \(x\)- axis

OpenStudy (anonymous):

what's the law?

OpenStudy (anonymous):

|dw:1358093656964:dw|

OpenStudy (anonymous):

in terms of h a's and k's?

OpenStudy (anonymous):

i have no idea what h's and k's are \(y=|x|\) looks like a V sitting right at the origin \((0,0)\) \(y=|x-2|\) looks like that same V moved to the right 2 units \(y=-|x-2|\) looks like that same V upside down, because of the minus sign out front (whatever was up is now down)

OpenStudy (anonymous):

so \[y=a|x+h|+k\] a positive h moves the v graph to the right, and negative h to the left how does the value of "a" effect the graph? does it make it upside down if it's negative?

OpenStudy (anonymous):

I guess I wrote that wrong, if h is positive the graph goes to the left and vice versa

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