Question

use the binomial theorem to expand the binomial. (3v+s)^5

Answer 1

@campbell_st

Answer 2

Possible answers :
s5 + 45s4v + 270s3v2 + 810s2v3 + 1215sv4 + 729v5
s5 + 15s4v + 90s3v2 + 270s2v3 + 405sv4 + 243v5
s5 + 15s4v + 90s3 + 270s2 + 405s + 243
s5 – 5s4v + 10s3v2 – 10s2v3 + 5sv4 – v5

Answer 3

@Butterfly16

Answer 4

ok... so pascal's triangle will give the coefficients



starting with (3v)^5 and (s)^0

decrease the power or 3v by 1 each time and increase the power of s

so you will have, using the last line of pascals triangle..

\[1 \times (3v)^5\times (s)^0 + 5\times (3v)^4\times(s)^1 + 10 \times (3v)^3 \times (s)^2 +...... \]

you need to continue until your have (3v)^0 and (s)^5