What is the third-degree polynomial function such that f(0) = -24 and whose zeros are 1, 2, and 3?

Question

anonymous · Answer

From the given data, we know that$$f)x)=k(x-1)(x-2)(x-3)$$To find k, we consider the given information about the value of the function at x=0$$f(0)=24=k(-1)(-2)(-3)=-6k \implies k=-4 $$$$\implies f(x)=-4(x-1)(x-2)(x-3)$$

anonymous · Answer

Depending on your author or teacher, you might have to multiply the factors out to put the answer in the desired form.

phi · Answer

I would tweak Animal's answer, as he solved for f(0)= 24  and you want f(0)= -24.  That means k = 4  (not -4)

can you multiply out 4(x-1)(x-2)(x-3) ?

As a first step, I would multiply (x-1)(x-2).  Can you do that ?