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Mathematics 9 Online
OpenStudy (anonymous):

Geometry...

OpenStudy (anonymous):

OpenStudy (anonymous):

Got any clue?

OpenStudy (anonymous):

Nice, no help at all....

jimthompson5910 (jim_thompson5910):

Ratio is 4:3, so Width: Height 4:3 4x:3x where x is some number, so width = 4x, height = 3x if the width is 4x and the height is 3x, and the diagonal is 42 in, then a^2 + b^2 = c^2 (4x)^2 + (3x)^2 = 42^2 16x^2 + 9x^2 = 1764 25x^2 = 1764 I'll let you finish

OpenStudy (anonymous):

Then you find the square root of 1764 and 15. \[\sqrt{25x}=\sqrt{1764}\] Is that right?

jimthompson5910 (jim_thompson5910):

first divide both sides by 25 then you take the square root of both sides

OpenStudy (anonymous):

Oh ok thanks! ... yeah I learned this, but the ratio they usually give is 4:1, not 4 to some other number. x^2 = 70.56 x=8.4

jimthompson5910 (jim_thompson5910):

now you use this value of x to find the width and height remember that width = 4x, height = 3x

OpenStudy (anonymous):

So I plug in the number 8.4 into the given places

jimthompson5910 (jim_thompson5910):

exactly

OpenStudy (anonymous):

4(8.4), 3(8.4) 33.6, 25.2

jimthompson5910 (jim_thompson5910):

so your answer is choice ___

OpenStudy (anonymous):

D. 33.6 and 25.2

jimthompson5910 (jim_thompson5910):

yep, you nailed it

jimthompson5910 (jim_thompson5910):

order is backwards, but it still works

OpenStudy (anonymous):

Yeah. haha thanks... I understand finding the angles, and classifying angles, but finding the sides always confuses me...

jimthompson5910 (jim_thompson5910):

just keep at it and you'll master it eventually

OpenStudy (anonymous):

Thanks again....

jimthompson5910 (jim_thompson5910):

yw

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