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Mathematics 14 Online
OpenStudy (anonymous):

(3i)^9

OpenStudy (anonymous):

3^9 (i)

OpenStudy (anonymous):

thanks, is it in the category of simplifying expressions

OpenStudy (anonymous):

that makes sense the i^9 is the tricky part

OpenStudy (anonymous):

yes it is. thank u for your help :)

OpenStudy (anonymous):

f(x)=10x^2-3x+5

OpenStudy (anonymous):

what am I doing? factoring?

OpenStudy (anonymous):

quadratic formula since there is an i

OpenStudy (anonymous):

yes, factor to solve

OpenStudy (anonymous):

\[\frac{ -3\pm \sqrt{9-200} }{ 20 }\]

OpenStudy (anonymous):

whooops +3

OpenStudy (anonymous):

alrite, am soo sorry i was talking about the discriminant and finding the solution

OpenStudy (anonymous):

9-200 = -191 so there are no real solutions or 2 complex solutions

OpenStudy (anonymous):

but were did u get the 9 and 200 from

OpenStudy (anonymous):

the discriminant is \[b ^{2}-4ac\]

OpenStudy (anonymous):

a=10 b=-3 c=5

OpenStudy (anonymous):

yeea

OpenStudy (anonymous):

i understand that part..

OpenStudy (anonymous):

the discriminant is b^2 -4ac if it is greater than 0, there are 2 real solutions if it equals 0 there is 1 real solution if it is less than 0, there are no real solutions or 2 complex solutions

OpenStudy (anonymous):

okay thank you :)

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