Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
3^9 (i)
OpenStudy (anonymous):
thanks, is it in the category of simplifying expressions
OpenStudy (anonymous):
that makes sense
the i^9 is the tricky part
OpenStudy (anonymous):
yes it is. thank u for your help :)
OpenStudy (anonymous):
f(x)=10x^2-3x+5
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
what am I doing? factoring?
OpenStudy (anonymous):
quadratic formula since there is an i
OpenStudy (anonymous):
yes, factor to solve
OpenStudy (anonymous):
\[\frac{ -3\pm \sqrt{9-200} }{ 20 }\]
OpenStudy (anonymous):
whooops +3
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
alrite, am soo sorry i was talking about the discriminant and finding the solution
OpenStudy (anonymous):
9-200 = -191 so there are no real solutions or 2 complex solutions
OpenStudy (anonymous):
but were did u get the 9 and 200 from
OpenStudy (anonymous):
the discriminant is \[b ^{2}-4ac\]
OpenStudy (anonymous):
a=10 b=-3 c=5
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
yeea
OpenStudy (anonymous):
i understand that part..
OpenStudy (anonymous):
the discriminant is b^2 -4ac
if it is greater than 0, there are 2 real solutions
if it equals 0 there is 1 real solution
if it is less than 0, there are no real solutions or 2 complex solutions