How to find the vertical asymptotes of the rational function g(x)=2x/x-8?

Question

anonymous · Answer

Do yo know how to use limits?

anonymous · Answer

No I've never solved this type of problem.

anonymous · Answer

Well, i'll supose you do, if you have a function f(x), there's a vertical asymptote x=x1 if

$$\lim_{x \rightarrow x1} f(x)= \infty$$ 

So, in your case, you have to 

$$\lim_{x \rightarrow x1} \dfrac {2x} {x-8} = \infty$$

Limits go to infinite when, for example their denominator goes to 0
Get it?

anonymous · Answer

So the answer choices are x=8; x=-8; x=2; none

anonymous · Answer

No not really.....

anonymous · Answer

Have you ever seen real function limits?

anonymous · Answer

No this is a problem our teacher gave us, but we've never gone over it.

anonymous · Answer

Aww, that turns it a little bit hard to explain, if you don't mind reading... http://www.mash.dept.shef.ac.uk/Resources/limits.pdf This explains what limits are- (It's precalculus stuff)

anonymous · Answer

Ok thanks.