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Mathematics 17 Online
OpenStudy (anonymous):

Determine if Odd, Even, or Neither: f(x)=|x|-1 f(x) =|x-2|

OpenStudy (anonymous):

do you know the definition of odd/even functions?

OpenStudy (anonymous):

it's even if f(x)=f(-x) right?

OpenStudy (anonymous):

even: \(\large f(x)=f(-x) \) odd: \(\large -f(x)=f(-x) \)

OpenStudy (anonymous):

uh... yes....

OpenStudy (precal):

also, if it is even then you will have symmetry with respect to the y axis|dw:1358135757527:dw|

OpenStudy (precal):

|dw:1358135782098:dw|if it is odd, you will have symmetry with respect to the origin

OpenStudy (anonymous):

okay so... like i got f(x)=x^2-2x. and i know that's even because it's also x^2- 2x when f(-x) when i do f(x) = |x|-1 i get f(-x) = |-x|-1 so.... ?

OpenStudy (anonymous):

great examples!!!

OpenStudy (precal):

|dw:1358135868660:dw|

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