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Mathematics 16 Online
OpenStudy (anonymous):

Determine the quantity of heat required to convert 1kg of ice at −20 degrees Celsius to water at 100 degrees Celsius? Specific heat capacities of water and ice water are 2302 J/kgK and 4186 J/kgK respectively

OpenStudy (anonymous):

I think you would use E = cm(change in temp) for the temp range of -20 to 0 degrees using the heat capacity of ice, then you would need to add the latent heat of fusion and finally add the answer to E = cm(change in temp) for the temp range of 0 to 100 degrees using the heat capacity of liquid water

OpenStudy (anonymous):

6.0×106J could it be the answer?

OpenStudy (anonymous):

Q=ms(delta theta) from -20 to 0, Q=1 x 4186 x 20 = 83720 at 0, add 336000 (latent heat of fusion of ice) finally, from 0 to 100 Q = 1 x 2302 x 100 = 230200 total 649920 or 6.49920x105

OpenStudy (anonymous):

thanks to every one

OpenStudy (anonymous):

The resulting temperature when 1kg of ice at 0 degrees Celcius is mixed with 9kg of water at 50 degress Celcius is ----------------------- to the nearest whole number.The specific capacity of water is 4200J/kg/K,the specific latent heat of fusion of ice is 330 000J/kg

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