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Mathematics 7 Online
OpenStudy (anonymous):

HELP!!!! What is the 8th term of the geometric sequence 4, -20, 100, ...?

Parth (parthkohli):

Basically, in a geometric sequence,\[A_n = A_1 \times r^{n - 1}\]

Parth (parthkohli):

Can you find the ratio, a.k.a \(r\)?

OpenStudy (anonymous):

i dont know how to do that

OpenStudy (anonymous):

-312,500 -12,500 62,500 1,562,500 these are the possible answers

OpenStudy (anonymous):

is it 62,500?

OpenStudy (anonymous):

use ar^{n-1} n is the last term of the sequence here value of n is 8. so put the value of n = 8 and a is your first term put a = 4. Common ratio that axr / a that means dividing next term by previous one you get this ratio here ratio is -5. So, solve this you get your answer

OpenStudy (anonymous):

is it -12,500? i just did what you said and thats what i got

OpenStudy (anonymous):

I got this −312,500

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