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HELP!!!! What is the 8th term of the geometric sequence 4, -20, 100, ...?
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Basically, in a geometric sequence,\[A_n = A_1 \times r^{n - 1}\]
Can you find the ratio, a.k.a \(r\)?
i dont know how to do that
-312,500 -12,500 62,500 1,562,500 these are the possible answers
is it 62,500?
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use ar^{n-1} n is the last term of the sequence here value of n is 8. so put the value of n = 8 and a is your first term put a = 4. Common ratio that axr / a that means dividing next term by previous one you get this ratio here ratio is -5. So, solve this you get your answer
is it -12,500? i just did what you said and thats what i got
I got this −312,500
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