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Evaluate the definite integral using the Fundamental Theorem of Calculus. Give your answer in exact form.
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\[\int\limits_{-1}^{1}1/(y^2+1) dy\]
Make the substitution y = tan x then y^2 + 1 = tan^2 x + 1 = sec^2 x and dy = sec^2 x dx It cancels out nicely. Remember to adjust the bounds.
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