Question

easy chain rule problem

Answer 1

back from winter break and having a brain fart: problem is: f(x)= \[\tan^3(5x)+\sin(7x^3-2x+1)\]

Answer 2

for the second half, the sin part, I got it's derivative to be \[\cos(7x^3-2x+1)(21x^2-2)\]

Answer 3

is that right so far?

Answer 4

so basically I just need to know the derivative of the tangent part

Answer 5

nevermind, figured it out!

Answer 6

correct

Answer 7

3tan^2(5x)* d/dx(tan5x)
=3(sin^2 (5x)/cos^2(5x))(sec^2( 5x)*5)
=15(sin^2 (5x)/cos^2(5x)(1/cos^2(5x)
=15(sin^2 (5x)/cos^4(5x)