Question

What is the simplest for of the radical expression?

https://www.connexus.com/content/media/680582-6112012-111146-AM-725267942.gif

Answer 1

Just to let you know, that link doesnt work.

Answer 2

\[3\sqrt{24}-2\sqrt{54}+2\sqrt{18}\]

Answer 3

Try simplifying each radical by finding the largest perfect square that fits into it (1,4,9,16,25,36,49,64...)

Answer 4

I dont really understand this stuff and its dude tonight and I can't fail

Answer 5

Is this a test?

Answer 6

no its not a test but its going to help me for the test

Answer 7

Ok, so can you find out which of those numbers goes into which perfect square?

Answer 8

Some hints: 24 = 4*6, 54 = 9*6, 18 = 9*2. \[\sqrt{24}=\sqrt{4*6}=\sqrt{4}*\sqrt{6}=2\sqrt{6}\]

Answer 9

I cant remember

Answer 10

@zaynahf and I just showed you everything you need to know.

Answer 11

okay.

Answer 12

so would it be \[5\sqrt{6}-3\sqrt{6}+3\sqrt{2}\]

Answer 13

and I have another problem

Answer 14

subtract \[2/ (4+\sqrt{6})-2/ (4-\sqrt{6})\]

Answer 15

Put it in another post, so others can answer too!

Answer 16

You made a mistake somewhere.

\[3\sqrt{24}-2\sqrt{54}+2\sqrt{18}=3\sqrt{4*6}-2\sqrt{9*6}+2\sqrt{2*9}=6\sqrt{6} -6\sqrt{6}+6\sqrt{2}=6\sqrt{2}\]

Answer 17

oh thank you

Answer 18

Oh, nuts, it doesn't show the whole width, but 6 sqrt(2) is the final answer.

Answer 19

The subtraction problem is just a matter of finding a common denominator.
\[\frac{2}{(4+\sqrt{6})}-\frac{2}{(4-\sqrt{6})}\]I would multiply the first fraction by \[\frac{(4-\sqrt{6})}{(4-\sqrt{6})}\] and the second fraction by \[\frac{(4+\sqrt{6})}{(4+\sqrt{6})}\] to get a common denominator. After the dust settles, you'll have a negative fraction with a different square root in there....