Question

Log11(25X+12) - log11 (x+3)=2

Answer 1

Try raising each term to the 11th power to "undo" the logarithm.

Answer 2

Well it's log base of 11, how would I raise that?

Answer 3

\[11^{\log_{11}25x+12 } - 11^{\log_{11}x+3 } = 11^{2}\]