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Chemistry 13 Online
OpenStudy (anonymous):

how many moles are in 665 g beryllium nitrate.. i forgot how to do these type of question.. need practice.. can someone show me how to do it. pleaseeeeee

OpenStudy (anonymous):

\[?mol Be(NO3)2 = 665 gr Be(NO3)2 \times ( \frac{ 1mol Be(NO3)2 }{133 gr Be(NO3)2 }) = 5 mol Be(NO3)2\]

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