Question

Help me pls :)
Simplify

Answer 1

\[\frac{ 9^{x} - 1 }{ 3^{x}-1 }\]

Answer 2

\[\frac{ 9^{x} - 1 }{ 3^{x}-1 }\]\[=\frac{ (3^2)^{x} - 1 }{ 3^{x}-1 }\]\[=\frac{ (3^x)^{2} - 1 }{ 3^{x}-1 }\]Use \(a^2-b^2 = (a+b)(a-b)\)to factorize the numerator.

Answer 3

thanks i understand i now

Answer 4

im sorry for the really late reply

Answer 5

It's okay :) Glad that you understand it now :)