Question

integratation of power of sines and cosines:

∫ sin^4 xcos^2xdx

Answer 1

this is calculus

Answer 2

\[-\frac{ \cos ^{5}x }{ 5 }+\frac{ \cos ^{7}x }{ 7 }+c\]

Answer 3

how come? what case did you used? is it case 2?

Answer 4

bak reyiz, cos^2 x=1-sin^2 x. biliyon mu bunu??

Answer 5

what? im sorry i cant understant your language, could you speak in english please?

Answer 6

can someone please help me? :(

Answer 7

I think it's not like what marsss did there...
\[∫ sin^4 xcos^2xdx\]\[=∫ sin^4 x(1-sin^2x)dx\]\[=∫ sin^4x-sin^6xdx\]\[=∫ (sin^2x)^2dx-∫(sin^2x)^3dx\]\[=\frac{1}{4}∫ (1-cos2x)^2dx-\frac{1}{8}∫(1-cos2x)^3dx\]\[=\frac{1}{4}∫ (1-2cos2x+cos^22x)dx-\frac{1}{8}∫(1-3cos2x+3cos^22x-cos^32x)dx\]
Reduce the power of cosine into 1 using doucle angle formula, except for cos^3(2x). Good luck :|