Question

solve 2x^2+3x-54

Answer 1

USE QUADRATIC FORMULA

Answer 2

yes

Answer 3

Here ya go...
2x^2+3x-54 =
2x^2 + 12x - 9x - 54 =
2x(x+6) -9(x+6) =
(x+6)(2x-9)

Answer 4

I hope that helps :)

Answer 5

omg thanks i have a few more if you dont mind

Answer 6

nope :)

Answer 7

1. 4w^2-11w+6
2.3t^2+13t-10
3. 8x^2+5x-3
4. 18z^2+17z+4

please show work :)

Answer 8

1. 4w^2-11w+6 = (w-2)(4w-3)
2.3t -13 = 2
+13 +13
Now, the -13 and the positive 13 cross out. And then you add 13 and 2.
So you should now have this:
3t = 15.
Now you just divide the 3t by 3 so you can get t alone. And whatever you do on one side, you have to do to the other. So you divide 15 by 3.

15 divided by 3 is 5. So the answer is:
t = 5

Answer 9

3. 8x^(2)+5x-3
In this problem 1*-(3)/(8)=-3 and 1-(3)/(8)=5, so insert 1 as the right hand term of one factor and -(3)/(8) as the right-hand term of the other factor.
(x1)(x-(3)/(8))
Remove the fraction by multiplying the first term of the factor by the denominator of the second term.
(x+1)(8x-3)

4. 8x^2+5x-3 = (8x-3)(x+1)

Answer 10

I hope thats all correct :) and I hope its helpful! :)

Answer 11

can u do 18z^2+17z+4 and 4w^2-11w+6 ..like how you do this
2x^2+3x-54 =
2x^2 + 12x - 9x - 54 =
2x(x+6) -9(x+6) =
(x+6)(2x-9
please an thank you

Answer 12

I got stuck on those two when I tried to use the same formula, I can use the quadratic formula?

Answer 13

okay

Answer 14

use it

Answer 15

18z^2+17z+4=0
X1 = -1/2
X2 = -4/9

4w^2-11w+6=0
X1 = 2
X2 = 3/4

Answer 16

is that better?