does anyone have the awnsers for Lesson 1: Rate of Change and Slope Algebra 1 A Unit 5: Linear Functions
i bet i know them name a question
i love algebra.....shoot the q
A line has slope –5/3. Through which two points could this line pass? (1 point)(12, 13), (17, 10) (16, 15), (13, 10) (0, 7), (3, 10) (11, 13), (8, 18)
What do you think it is?
i havnt the slightest clue i dont even know how to do it
you need to compute four slopes for this one problem
and how do u do that
but we can cheat a little i think in general the slope is \(\frac{y_2-y_1}{x_2-x_1}\) now the first one the numerator would be \(10-13=-3\) so forget that one
@omgineedhlp I guess i answered the same ques in your last post.
for \[(16, 15), (13, 10)\] we compute \[\frac{10-15}{13-16}=\frac{-5}{-3}=\frac{5}{3}\] so it is not that one
lets try \[(11, 13), (8, 18)\] \[\frac{18-13}{8-11}=\frac{5}{-3}=-\frac{5}{3}\] got it on the last try
ok so 11,13 the 11 is x1?
The pair of points (6, y) and (10, –1) lie on a line with slope . What is the value of y? (1 point)–5 –2 2 5
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