Mr.Tanaka is 35 years old, and his son is 5. In how many years will Mr. Tanaka be three times as old as his son?
In some unknown number of years, Mr Tanaka will be \(\large 35+x\) years old. When the same amount of years have passed, the son will be \(\large 5+x\) years old. If Mr Tanaka is 3 times as old as the son when these years have passed, we can write it like this,\[\large 35+x=3(5+x)\]From here we can solve for X, the number of years that have passed by.
but whats the answer?
To solve for x, first, distribute the 3 to each term inside the brackets,\[\large 35+x=15+3x\] Then subtract x from each side,\[\large 35=15+2x\]Then subtract 15 from each side,\[\large 20=2x\]Then finally divide both sides by 2. This will tell us the number of years that need to pass in order for the Father's age to be 3 times that of the son's.
what is the answer
i don't understand algebra so that's why i came on here
That's not the purpose of this website I'm afraid - to just give you answers :( I showed you the entire process. If you're still struggling with it maybe you should get a tutor.. or study more :c Look over the steps. It's a bit of a tricky problem, I know.
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