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Mathematics 12 Online
OpenStudy (anonymous):

solve 1/2 - sin x=1

OpenStudy (zehanz):

First, try to see what sin x would have to be (hint: 1/2 - -1/2 = 1)

OpenStudy (anonymous):

1

OpenStudy (zehanz):

Yes, so this means sin x = -1/2, because 1/2 - - 1/2 = 1. Now you have to solve: sin x = -1/2. Do you know how to do that?

OpenStudy (anonymous):

no

OpenStudy (zehanz):

It has to do with "known" (?) values of the sine function, e.g. Everyone has to remember that: sin 0 = 0 sin(pi/6)= 1/2 sin((pi/4)=1/2 sqrt(2) Do you know these values also?

OpenStudy (anonymous):

kinda

OpenStudy (anonymous):

im new to this stuff

OpenStudy (zehanz):

But you know about the unit circle, not?

OpenStudy (anonymous):

yes

OpenStudy (zehanz):

OK, I'll draw one for you with sin x = -1/2, hold on, please

OpenStudy (zehanz):

Almost done ;)

OpenStudy (zehanz):

This is the unit circle.

OpenStudy (zehanz):

Definition of sin: If you want to know what the sine of a number (angle) is, do this: draw the angle from the positive x-axis, in anti-clockwise direction. The angle meets the circle in a certain point. The y-coordinate of that point is the sine of the angle. In my drawing, I have done it the other way round, because I already know the sine, but not the angle. So I've drawn a horizontal line at height -1/2. Where it intersects the unit circle, lines to the origin have been drawn. Now you can see there are two angles, alpha and beta, that will have a sine of -1/2. Does this make any sense to you?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

x= pi?

OpenStudy (zehanz):

Ok, If you look at the bottom half of the circle, you'll see alpha and beta. What are their values? The triangles there must look familiar! They are 30-60-90 degree triangles (don't know how you call them, but they are well known...)

OpenStudy (zehanz):

So \[\alpha = -30 \deg =-\frac{ \pi }{ 6 }\]

OpenStudy (anonymous):

so its - pi/6?

OpenStudy (zehanz):

Yes, and the other one is 180+30=210 degrees, or 7pi/6

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