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OpenStudy (anonymous):
 sin^2 theta + cos theta =2 (Hint: Use the Pythagorean identity sin^2 theta +cos^2 theta =1 to replace sin^2 theta in the given equation).
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OpenStudy (lalaly):
first solve for sin^2theta in the second equation, do you know how?
OpenStudy (anonymous):
0?
OpenStudy (lalaly):
\[\sin^2\theta+\cos^2\theta=1\]therefore\[\sin^2\theta=1-\cos^2\theta\] replacee the sin^2theta in ur first equation by the one i jus found
OpenStudy (anonymous):
so 1-cos^2 theta +cos^2 theta =1
OpenStudy (lalaly):
yes
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OpenStudy (anonymous):
so thats my answer?
OpenStudy (lalaly):
but wait you wrote 1-cos^2 theta +cos^2 theta =1 its \[1-\cos^2\theta+\cos \theta =1\]
OpenStudy (lalaly):
if u are asked to find theta, then u just solve for costheta and find the value of theta
OpenStudy (lalaly):
=2*
OpenStudy (lalaly):
\[1-\cos^2\theta+\cos \theta=2\]
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