Question

y=z(z-17)/2, y=0

Answer 1

If you have the product of 2 two numbers (z, and z-17), what must be true for that product to be 0?

Answer 2

Hint: 0*x = 0 for all values of x

Answer 3

one must be zero

Answer 4

At least one of them...

Answer 5

So what are your values of z that make y = 0?

Answer 6

so the division of 2 doesnt matter in this question

Answer 7

Exactly. You can multiply or divide both sides by any number (except 0) without changing the underlying truth of the equation, or the solutions.

Answer 8

so in order to find the other z i have to plug in 0 to the first z

Answer 9

Mmm...no. :-)

Answer 10

so z=0

Answer 11

If you have a polynomial (x+a)(x+b)(x+c)... = 0, the solutions are x = -a, x = -b, x = -c, etc. Basically, set each term equal to zero and solve. You've solved the (z + 0) = 0 term. How about the other one?

Answer 12

z-17=0
z=17

Answer 13

Bingo!

Answer 14

Now that you know the trick, you could look at this one and solve it in seconds:

(x+3)(x-4) = 0

Answer 15

-3, 4

Answer 16

oh wait the problem is divided by z not 2

Answer 17

Oh, sure, now you tell me :-)

Answer 18

haha I barely just realized

Answer 19

So that is \[y=\frac{z(z-17)}{z}\]?

Answer 20

yea

Answer 21

Okay, if anything, this one is easier. You've got a common factor in numerator and denominator that you can cancel.
\[y=\frac{z(z-17)}{z} = (z-17)\]

I bet you can find the solution that makes y = 0 :-)

Answer 22

17 :)

Answer 23

A hot babe who can do math. What's not to like? :-)