If I am trying to find the area between two curves and on of the functions is x=(y^3)-y, how do I graph that function?

Question

zepdrix · Answer

I don't think there's a easy way to graph this.

You certainly could take the derivative and find critical points and inflection points and graph it that way.
But that sounds tedious.

It might be a better idea to try and solve it without graphing it.
It's possible you could be given a problem like that on a test - where it's not too hard to solve, but very very difficult to visualize.

BTW, What is the other function? c:

babyslapmafro · Answer

x=0

babyslapmafro · Answer

maybe asking how to graph x=(y^3)-y is a bad question.  How do I find out which is the rightmost bounding function?

zepdrix · Answer

Hmm it turns out it's x=0... But I had to use a program to graph it to realize that.

Hmmmmmmm... thinkingggg

zepdrix · Answer

Oh ok let's try this.

zepdrix · Answer

If we find intersecting points...$$\large x=y^3-y, \qquad x=0$$Setting these equal to one another will give us intersecting points.$$\large 0=y^3-y \qquad \rightarrow \qquad 0=y(y^2-1)$$So it looks like we have intersecting points at y=0, y=-1, y=1..... hmmm

zepdrix · Answer

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Sorry I'm a little confused by this question...
There appears to be 2 separate regions... see how one is to the left of x=0 and another to the right of x=0?