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Mathematics 16 Online
OpenStudy (anonymous):

f(x)=x+cosx on [-2π,2π] how to find the critical numbers

OpenStudy (anonymous):

First find the derivative

OpenStudy (anonymous):

well ya its 1-sinx

OpenStudy (anonymous):

Good. Now find when the derivative equals 0. This is a bit trickier

OpenStudy (anonymous):

i know the answer is -3/2pi and pi/2 but i have no idea why

OpenStudy (anonymous):

so 1-sinx=0 sinx = 1 Look at the unit circle. When does sin = 1?

OpenStudy (anonymous):

sin means the y-coordinate of the angle btw

OpenStudy (anonymous):

2pi?

OpenStudy (anonymous):

no i mean pi/2

OpenStudy (anonymous):

oh its also -3/2pi cus on the unit circle -1 is 3/2pi....so you just do the opposite right?

OpenStudy (anonymous):

No you explained it wrong. That's just a coincidence. sin(pi/2) = 1, for sure. Now the range is [-2π,2π] so it menas you can go clockwise or anti-clockwise from 0. If you go counterclockwise you get pi/2. If you go clockwise, you get to -3pi/2.

OpenStudy (anonymous):

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