Question

What are the zeros of x^3+8=0? (hint: factor and solve)

Answer 1

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Answer 2

factor as the sum of two cubes
\[a^3+b^3=(a+b)(a^2-ab+b^2)\]

Answer 3

in your case you get
\[(x+2)(x^2-2x+4)=0\]

Answer 4

first factor gives the real zero \(x=-2\) second factor gives two complex zeros via the quadratic formula

Answer 5

if you are not looking for complex zeros, then it would be a lot easier to write
\[x^3=-8\] and get \(x=-2\) by inspection

Answer 6

how do you use the quadratic formula in this?

Answer 7

@satellite73

Answer 8

oh i understand, thank you :]