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find second derivative of e^(8x) +3cos(x)sin(x)
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\[e ^{8x} +3\sin(x)\cos(x)\]
for the first derivative I got \[8e ^{8x} +3\cos^2x-3\sin^2x\] is that right so far?
Yes, I believe so, your first derivative looks correct.
but then I get confused about how to get the derivative of that
Well, we take it in steps, the first part is just \[64e ^{8x}\]Second and third portion use the chain rule. Second portion:\[-6cosx*sinx\] and third portion: \[-6sinx*cosx\]
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