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Chemistry 11 Online
OpenStudy (anonymous):

A solution contains 180 g of glucose (C6H12O6) and 162 g of water. What is the mole fraction of glucose?

OpenStudy (aaronq):

\[\chi _{glucose}= \frac{ n _{glucose} }{ n _{glucose}+n _{water} }\]

OpenStudy (aaronq):

n = moles

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