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Mathematics 10 Online
OpenStudy (anonymous):

Are These Vectors Parellel? u = <9, 3>, v = <36, 12>

zepdrix (zepdrix):

If they are parallel, then they will be constant multiples of one another. How can we change the 36 to 9? Let's divide a 4 out of it. We'll also take the 4 out of the 12, if the 12 gives us a 3 while the 36 gives us a 9, then they are parallel.\[\large \vec u=<9,3>, \qquad \vec v=4<9,3>\]Understand what I did there? I factored a 4 out of each component in vector v.

zepdrix (zepdrix):

We can clearly see that V is 4 times U. It's a CONSTANT MULTIPLE of U. V=4U

OpenStudy (anonymous):

ohhh so just factor each vector and that is how you get your answer! So they are parellel since you were able to factor the same vector! right?

zepdrix (zepdrix):

Yes, good! :D

OpenStudy (anonymous):

Thank you so mcuh!

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