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Are These Vectors Parellel? u = <9, 3>, v = <36, 12>
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If they are parallel, then they will be constant multiples of one another. How can we change the 36 to 9? Let's divide a 4 out of it. We'll also take the 4 out of the 12, if the 12 gives us a 3 while the 36 gives us a 9, then they are parallel.\[\large \vec u=<9,3>, \qquad \vec v=4<9,3>\]Understand what I did there? I factored a 4 out of each component in vector v.
We can clearly see that V is 4 times U. It's a CONSTANT MULTIPLE of U. V=4U
ohhh so just factor each vector and that is how you get your answer! So they are parellel since you were able to factor the same vector! right?
Yes, good! :D
Thank you so mcuh!
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