Question

Find any points of discontinuity for the rational function. y = ((x +6)(x + 2)(x + 8))/((x + 9)(x + 7))

x = 6, x = 2, x = 8
x = 9 x = 7
x = –9, x = –7
x = –6, x = –2, x = –8

Answer 1

\[\frac{ (x +6)(x + 2)(x + 8) }{ (x + 9)(x + 7) }\]

Answer 2

These are pretty easy to find actually. In a rational function, we already know that the denominator can not equal 0.

So to find a point of discontinuity, we just need to look at the denominator and set it equal to 0.

Answer 3

In this case (x+9)(x+7) = 0

So we set each one to equal 0
(x+9) = 0
(x+7) = 0

And the answers will tell us the points of discontinuity.

Answer 4

@cgreenwade2000 so x = -9 and x = -7

Answer 5

Correct. And can you see that if x = -9, the denominator is 0 and if x=-7, then the denominator = 0?