Please help I don't think there is a way to solve this problem. I don't think there is enough info. Thanks for your time A box with a square base has a volume of 12 cubic feet. How high should the box be in order that it has the minimal surface area. has a top and 6 sides
please please help
so it looks like we need to define a volume of a box that is 12 cubic feet ... and work some derivatives
do you know a general equation for surface area of a box with a square base?
|dw:1358369719202:dw|
Sa = 4sh + 2s^2 V = s^2 h = 12 h = 12/s^2 Sa = 4s(12/s^2) + 2s^2 = 48s^(-1) + 2s^2 when we know s, we should then be able to solve for h
Is the right answer for h 0.0833333
dunno, i havent had the chance to work it out :) ill check on it when i can leter.
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