Rewrite with only sin x and cos x. cos 3x
\[\large \cos(3x)=\cos(2x+x)\]From here we can apply the Angle Addition Formula for Cosine.\[\large \cos(2x+x)=\color{cornflowerblue}{\cos(2x)}\cos x-\color{orangered}{\sin(2x)} \sin x\]And from here, we can apply the Cosine Double Angle Formula to the \(\color{cornflowerblue}{\cos(2x)}\) and the Sine Double Angle Formula to the \(\color{orangered}{\sin(2x)}\).\[\large =\left(\color{cornflowerblue}{\cos^2x-\sin^2x}\right)\cos x-\left(\color{orangered}{2\sin x \cos x}\right)\sin x\] Andddd you can simplify it down a bit from here. But everything is in terms of an Angle X instead of 2x or 3x now, so that's good!
Oh that's really annoying... They said rewrite with ONLY sinx and cosx.... yet all of your multiple choices have sin2x or sin3x in them... what a stupid question :\ Hmmmm
Oh maybe I'm reading it incorrectly because powers don't copy paste very well. Like option number 1, is that suppose to be: \[\large \cos x-4\cos x \sin^2x\] Or\[\large \cos x-4\cos x \sin (2x)\]
I was asking a question....
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