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Mathematics 13 Online
OpenStudy (anonymous):

I need help with finding the percentage. I'm confused on this problem. Will someone walk me through the steps? A local zoo has on average 250 visitors per day during its peak season with a standard deviation of 80. Assume that the variable is normally distributed. 1. Find the probability that the zoo will have less than 100 visitors.

jimthompson5910 (jim_thompson5910):

are you allowed to use a calculator

OpenStudy (anonymous):

Yes

jimthompson5910 (jim_thompson5910):

do you have a TI calculator?

OpenStudy (anonymous):

Nope.

jimthompson5910 (jim_thompson5910):

ok then we'll have to use wolfram alpha

OpenStudy (anonymous):

Alright. So what would I do?

jimthompson5910 (jim_thompson5910):

you would type this in normalcdf(0,100,250,80) the first two numbers 0 and 100 represent the interval under the curve we want to find, basically we want the area under the curve from 0 to 100 the next two numbers are the mean (250) and the standard deviation (80)

jimthompson5910 (jim_thompson5910):

if you type that in, you'll get this link http://www.wolframalpha.com/input/?i=normalcdf%280%2C100%2C250%2C80%29

jimthompson5910 (jim_thompson5910):

now look at the row that says 0 < z < 100 next to that is the number 0.02951

jimthompson5910 (jim_thompson5910):

so the area under the curve from 0 to 100 is 0.02951 this means that the probability is roughly 0.02951 (which is a 2.951% chance roughly)

OpenStudy (anonymous):

Thank you very much.

jimthompson5910 (jim_thompson5910):

yw

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