Question

\[sin(2~arc~cos{3\over5})\]i forgot how to do this...

Answer 1

@artofspeed

Answer 2

@Hero

Answer 3

sin(2x)=2 * sinx * cos x

Answer 4

arccos(3/5) = x can be drawn as

Answer 5

hence the third side is sqrt(5^2-3^2)=4

Answer 6

sinx = 4/5 and cosx=3/5

Answer 7

sin(2x)=2 * sinx * cos x = 2*4/5*3/5 = 24/25

Answer 8

i dont get how sin2x=2sinxcosx

Answer 9

nevermind...

Answer 10

thanks @artofspeed ! :)

Answer 11

nooo problem

Answer 12

lol :D