I have a couple of questions I need help solving them please don't give me the answer. -Solve 4x + 3y = 8x + y for y -Which of the following ordered pairs is a solution of y < 2x -6?
Hello there, I think I can help you!
Please .. I don't want the answers I just want help getting there.
Sure thing, what do you seem to be having trouble with?
Really starting the problems ...
About those two problems.
Yes ..
Ah, okay, well let's look at the first one.
Ok... I keep writing every way but, none of my ways match the answers ....
4x + 3y = 8x + y for y The goal here is to get y all on one side, and get all the x's on the other.
So what do I add the 4x+8x and the 3y+y ?
\[ 4x + 3y = 8x + y\]\[ 4x + 3y - y = 8x\]\[ 4x + 2y = 8x\]\[2y = 8x - 4x\]\[2y = 4x\]\[y = 4x/2\]\[y = 2x\]
I posted the steps one by one. Do you need a numerical value for y? or just one that contains x?
Okay .. I see exactly what I did wrong ...
Ah, glad to hear that.
Now the next one?
Yes me too .. Because I would've guessed ... :o We don't want that
Which of the following ordered pairs is a solution of y < 2x -6?
Can you list the ordered pairs?
yes
Here you go (0,5) (2, -3) (5, 8)
Okay, so the goal here is to plug in each ordered pair into y < 2x -6 and see which one makes that statement true.
Ok... So how do we do that .. Do we solve the problem ?
So, for the first one, we plug in 0 to x, and 5 to y, and get 5 < 2(0) - 6, which comes out to be 5 < -6, which is false because -6 is less than 5, so we throw that one out and go to the next one.
Ohhhh ... I see.
So it's b?
y < 2x -6, -3 < 4 - 6, -3 < -2 which is true, so yeah looks like it.
You are amazing ... Thank you so much !
Thank you, and good luck. :)
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