Person will get medal and fan if they help. *NEED STEP BY STEP INSTRUCTIONS* Joe deposits $1,500 in an account that pays 3% annual interest compounded continuously. a. How much will Joe have in his account after 5 years? b. How long will it take Joe to double his money? Use natural logarithms and explain your answer.
Use the formula: A = Pe^(rt) Where P is the amount you start with (1,500) r is the rate (.05) in this case and t is time (after 5 years so t = 5) Can you solve question a from here?
Sorry the rate is (.03)
yes hold on
So this is the equation. 1500e^1.5?
e^.15 (.03 * 5) = .15
For a. i got 1500e^1.5 = 6722.53
Nope, you should have gotten 1742.75 You know what e is on your calculator right?
yeah.
I entered it like this into the calculator 1500e^(.03*5)
Ok now i got it. so it is 1742.75
it's like 1742.751364 (I don't know how much you need to round).
Its just to the tenth. now can you help me with part b? That is the harder part
Sure
This time we know what we need to get to double our money. 1500 * 2 = 3000 So put 3000 in for A in the equation we used before 3000 = 1500e(.03t) What we don't know is time. So we will solve for it. 3000 / 1500 = e^.03t 2 = e^.03t Now take the natural logarithm ON BOTH SIDES to get rid of e ln(2) = ln(e)^.03t This is important because ln(e) = 1 !!!! ln(2) = .03t ln(2) / 3 = t t = 23.1 years Understand?
The first part should read 3000 = 1500e^(.03t) I forgot to raise e to the power, but the rest is correct.
THANK YOU SO MUCH!
No probs! Anytime :)
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