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suppose S (0 to 1) f(t)dt =3 calculate the following:
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\[\int\limits_{0}^{1}f(t)dt=3 calculate the following: \]
\[\int\limits_{0}^{.5}f(2t)dt\]
f(x)=1/(x+1) vs f(2x)=1(2x+1) f(x)=x^2 vs f(2x)=4x^2 Can you make any comparison to functions you can easily find the integral of to determine some pattern?
they are similar
\[\int\limits_{2a}^{2b}f(2t)dt=\frac{ 1 }{ 2 } \int\limits_{a}^{b}f(u)du=\frac{ 1 }{ 2 } \int\limits_{a}^{b}f(t)dt\] \[\int\limits_{0}^{0.5}f(2t)dt=\frac{ 1 }{ 2 } \int\limits_{0}^{2}f(u)du=\frac{ 1 }{ 2 } \int\limits_{0}^{2}f(t)dt=\frac{3}{2}\]
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because by get u=2t we have du=2 dt
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