Mathematics
10 Online
OpenStudy (anonymous):
Integrate the following:
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OpenStudy (anonymous):
\[∫ \sqrt{\frac{ 2 }{ 5x }} dx\]
OpenStudy (anonymous):
\[\int\limits_{}^{}\frac{ (2/5)^\frac{ 1 }{ 2 } }{ x^\frac{ 1 }{ 2 }}\]
OpenStudy (blurbendy):
@bmelyk did you figure out the other one?
OpenStudy (anonymous):
is that the first step?
OpenStudy (anonymous):
well you can go about this many ways, but personally that's how i start
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OpenStudy (anonymous):
okay so then what
OpenStudy (anonymous):
well the 2/5 is a constant, so you really only need to worry about x
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
\[(\frac{ 2 }{ 5 })^\frac{ 1 }{ 2 }\int\limits_{}^{}(\frac{ 1 }{ x })^\frac{ 1 }{ 2}\]
OpenStudy (anonymous):
thats what i have so far.
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OpenStudy (anonymous):
(1/x)^(1/2) is also just x^(-1/2)
OpenStudy (anonymous):
okie
OpenStudy (anonymous):
so then just integrate x^(-1/2)
OpenStudy (anonymous):
how do i go about that? lol, we just started this course last week
OpenStudy (anonymous):
ill just use my formula, right?
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OpenStudy (anonymous):
um i dont know what you mean by formula, but anytime you integrate you are raising x by a power. So like x would become (x^2)/2.
OpenStudy (anonymous):
i got: \[\sqrt{\frac{ 2 }{ 5 }} \frac{ -2 }{ 3 } x ^{\frac{ -3 }{ 2 }} +c\]
OpenStudy (anonymous):
Close, but you took the derivative of x (kinda)
x^(-1/2) would become 2x^(1/2)
-1/2+1=1/2
OpenStudy (anonymous):
so its\[\sqrt{\frac{ 2 }{ 5 }} 2\sqrt{x}+c?\]
OpenStudy (anonymous):
yes i believe so
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OpenStudy (anonymous):
can you help me with antoher'?
OpenStudy (anonymous):
sure
OpenStudy (anonymous):
okay... \[∫ (\sec^23x+\frac{ 1 }{ 3x }) dx\]
OpenStudy (anonymous):
alright, well \[\sec ^2x \] is a known derivative of tanx
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
1/x is the derivative of natural log
OpenStudy (anonymous):
yes