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Please help. I've been working on this for hours/: Let f(x)=x^2+6 and g(x)=(x+8)/x. Find (g o f)(-7) a) -55/7 b) 384/7 c) 295/49 d) 63/55 ANY help would be VErY much appreciated .(:
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find f(7) first then what you get for that you put it in as x of g(x)
\[f(-7)=(-7)^2+6=55\] now find \(g(55)\)
\[g(55)=\frac{55+8}{55}\] etc
Wait what? I'm confused.....
Plut -7 into the f(x) function first.
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Ok. so f(-7)=(-7)^2+6=55 rigt?
yes, not you take the 55 and put it into the g(x) function
So it's g(55)=(55+8)/x
good, but also put 55 in for the x on the bottom.
Oh right. My bad. So g(55)=(55+8)/55 = g(55)=63/55 ?
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there you go
So the answer is 63/55?
yes
Thank you so much!!
Would you be able to help me with one more?
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i can try
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