The region bounded by the given curves is rotated about the specified axis. Find the volume V of the resulting solid by any method.
x = (y − 5)^2, x = 4; about y = 3
I am trying to use the disc method but I am not sure how I would.
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OpenStudy (anonymous):
Anyone want to help me set up the integral?
OpenStudy (anonymous):
Anyone? :( .
OpenStudy (anonymous):
Well I found the intersection points for y which are y=3 and y=7.
OpenStudy (tkhunny):
Good. This is a nice problem. Have you heard of Pappus's Theorem?
OpenStudy (anonymous):
No.
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OpenStudy (tkhunny):
Too bad. It is much simpler with the Centroid. Another lesson on another day, perhaps.
The Whole thing: \(\pi\int\limits_{0}^{4}(y_{1}-3)^{2}\;dx\)
The Extra thing: \(\pi\int\limits_{0}^{4}(y_{2}-3)^{2}\;dx\)
Do you see the nature of the problem that requires two definitions for 'y'? It's NOT a function!
OpenStudy (anonymous):
Yeah, I realized that.
OpenStudy (tkhunny):
Perfect. What are the two definitions?
OpenStudy (anonymous):
Wait you lost me. Never mind.
OpenStudy (anonymous):
@tkhunny
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OpenStudy (tkhunny):
\(x = (y-5)^{2}\)
Solve for \(y\). You should get TWO results.
OpenStudy (anonymous):
yeah y=y-5 and y=5-y
OpenStudy (anonymous):
Wait. WHat am I doing...
OpenStudy (anonymous):
Braid dead lol.
OpenStudy (tkhunny):
?? Where did the \(x\) go?
\(\sqrt{x} = y-5\;for\;y>5\)
\(\sqrt{x} = 5-y\;for\;y<5\)
Keep solving!
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