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State the horizontal asymptote of the rational function. f(x) =(x+9)/(x^2+8x+5)
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the degree of the numerator is 1, the degree of the denominator is 2 since the denominator has a larger degree, the horizontal asymptote is \(y=0\)
to find the vertical asymptotes, set \(x^2+8x+5=0\) and solve for \(x\)
this one doesn't factor, but you can complete the square easily \[x^2+8x+5=0\] \[x^2+8x=-5\] \[(x+4)^2=-5+16=11\] \[x+4=\pm\sqrt{11}\] \[x=-4\pm\sqrt{11}\]
look at first post, answer is there
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