Question

Methane (CH4), ammonia (NH3), and oxygen (O2) can react to form hydrogen cyanide (HCN) and water according to this equation:
CH4 + NH3 + O2  HCN + H2O
You have 8 g of methane and 10 g of ammonia in excess oxygen. Answer the following questions:
• What is the balanced equation for this reaction?
• Which reagent is limiting? Explain why.
• How many grams of hydrogen cyanide will be formed? Show your work.

Answer 1

Actually this is all I need to know. How many grams of hydrogen cyanide will be formed? Show your work.
I've already got the other two.

Answer 2

Each chemical in the equation has 1 mol right?

Answer 3

I think so.

Answer 4

HCN is composed of 1 H, 1C, and 1N right? Looking at the equation, that's going to come from 1CH4 and1NH3.

Answer 5

CH4 has 16.04 g/mol, and NH3 has 17.035 g/mol. So, figure out how many moles each has given the grams, and whichever one has the lowest number is your answer.

Answer 6

Since it's a 1:1 mole ratio for HCN

Answer 7

Could you tell me how to figure that out ? I don't know how.

Answer 8

CH4: 8 grams * 1 mol/16.04 grams = ?

Answer 9

NH3: 10 grams * 1 mol/ 17.03 grams. The grams cancel out, giving you the number of moles.

Answer 10

2.005 ??

Answer 11

Ohh okay so its Nh3 has 10 and CH4 has 8

Answer 12

So the answer is CH4 beacause it has less

Answer 13

Did you multiply and divide the equations I showed you?

Answer 14

CH4: 8/16.04 mol
NH3: 10/ 17.03 mol.

Answer 15

What does it come to?

Answer 16

CH4 was 2.005
And NH3 was 1.703 ?
Is that right ?

Answer 17

Remember, it's 8/16.04, NOT 16.04/8.

Answer 18

Well I got .49875 that doesn't sound right

Answer 19

Yes, it's right. There are only 8 grams of CH4, and it takes about 16 grams to make one mol of CH4. You have half of what is necessary, so you have around .5. Good job!
Do the same with NH3, and the limiting reactant is your answer!

Answer 20

Well, the mol number of the limiting reactant.

Answer 21

CH4:.49875
NH3: .5871
So the answer is CH4

Answer 22

Close, CH4 is the limiting reactant.The question is:How many grams of hydrogen cyanide will be formed? Show your work.

CH4 will use .49875 mol to make HCN. Since it's the limiting reactant, .49875 mol HCN will be produced.

Answer 23

.49875 mol HCN is your answer.

Answer 24

Thank you alot :)

Answer 25

No problem!