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OpenStudy (anonymous):
How many moles of air are in 2.7L at 250K and 93kPa?
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OpenStudy (anonymous):
My work: PV = nRT V = 2.7L T = 250K P = 93kPa R = 8.314 *kPa /mol*K 93kPa * 2.7L =n(8.314 *kPa /mol*K)250K --> 251.1 = 2078.5n, n = 0.120808
OpenStudy (anonymous):
@ParthKohli @sauravshakya
OpenStudy (anonymous):
@ghazi @Yahoo! @hba
OpenStudy (anonymous):
working with LaurAK on her problem. Just so you know.
OpenStudy (jfraser):
that's what i got
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OpenStudy (anonymous):
Great, thanks!
OpenStudy (anonymous):
Could you check another one please?
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