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Mathematics 8 Online
OpenStudy (anonymous):

simplify the rational expression. State any restrictions on the variable.

OpenStudy (anonymous):

OpenStudy (anonymous):

A. q+8/q-8 ; q ≠ –3, q ≠ –8 B. -(q+8)/ q-8 ; q ≠ 8 C. q+8/q-8 ; q ≠ –3, q ≠ 8 D. -(q+8)/q-8 ; q ≠ –3, q ≠ 8

OpenStudy (zehanz):

First try to factor both numerator and denominator. You get: Numerator: q²+11q+24=(q+a)(q+b), where a+b=11 and ab=24, so a=..., b=... Denominator: q²-5q-24=(q+c)(q+d), where c+d=-5 and cd=-24, so c=..., d=... Hint: I always try the product (ab, cd) first, because there are not many "nice" numbers that will do the trick: 1*24 - no: sum is not 11 2*12 - no: sum is not 11 3*8 - YES! sum is 11! After doing this, you'll see common factors which can be canceled. Just remember that dividing by 0 is bad, so exclude the values that make the denominator 0.

OpenStudy (anonymous):

so its c?

OpenStudy (anonymous):

or a ?

OpenStudy (anonymous):

@ZeHanz

OpenStudy (zehanz):

Hold on, I'm typing ;)

OpenStudy (zehanz):

\[\frac{ (q+3)(q+8) }{ (q+3)(q-8) }=\frac{ q+8 }{ q-8 }\]Of course, q may not be -3, also not 8, so I get answer C. You are right!

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