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Solve the equation. log(x + 9) – log x = 3
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ok... do you know about the log law for division...?
\[\log (\frac{a}{b} )= \log(a) - \log(b) \]
you also need to know about raising the log to a power of the base \[a^{\log_{a}(x)} = x\] and you appear to be working with base 10 logs so you have \[\log(\frac{x + 9}{x} )= 3\] raise them to the power of 10 so \[\frac{x + 9}{x} = 10^3\] now you can solve for x
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