There are 7 women and 3 men. How can a jury be made up if 5 women must be choosen and 2 men must be choosen? Next, consider the case if 2 men are arguing and cannot be on the same jury, now how many jurys can be made up?

Question

There are 7 women and 3 men.  How can a jury be made up if 5 women must be choosen and 2 men must be choosen?  Next, consider the case if 2 men are arguing and cannot be on the same jury, now how many jurys can be made up?

anonymous · Answer

I know i have to use combinations, but how?

anonymous · Answer

What grade is this my dear boy?

anonymous · Answer

5th grade

anonymous · Answer

I should be able to help. I'm in Honors 9th. God Forbid I don't.

anonymous · Answer

I honestlt don't know. I'm soo sorry.

kropot72 · Answer

In the first section the number of ways is:
7C5 * 3C2

anonymous · Answer

I need help with the second part

kropot72 · Answer

For the second part, the number of combinations of women is the same as the first part: 7C5.
Let the 3 men be identified as A, B and C. Assuming that A and C cannot be on the jury together, how many combinations of men are possible?

anonymous · Answer

2C2*5C1

anonymous · Answer

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